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Congratulations to my brother Marcelo Balat for presentation in the theater Libertador General San Martin cordodoba city, in which he played a Beethoven work together the symphony of Cordoba province and soon in Valencia will be present.

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photos on the half marathon national championship

A cold morning with a temperature of 4 degrees dawns the city of Buenos Aires and a gentle south wind.

In the forests of Palermo is prepared especially for the start of the national championship half-marathon in which I was in representation of the city of cordoba with bib No. 53, long in the area of \u200b\u200belite and in which I had a good performance but finish the race with a time of 1h33m32s.

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Sum of Matrices in Dev-C + +

Carrying out a program that allows the sum of matrices in a recurrent exercise programming courses, and can structure the program easier if you have knowledge of linear algebra .

then the code for adding 2 arrays must have equal number of both rows and columns.

 
  # include \u0026lt;iostream>  
 
   using namespace std; 
 
   int row, fil, i, j; 
 
   int main () 
 
 {court \u0026lt;\u0026lt;" Enter the number of rows "\u0026lt;\u0026lt;endl; 
 cin>> fil; 
 court \u0026lt;\u0026lt;"Enter the number of columns" \u0026lt;\u0026lt;endl; 
 cin>> row; 
   int array1 [fil] [row]; 
  for  (i = 0; i \u0026lt;= fil-1, i + +) 
 {
  for  (j = 0, j \u0026lt;= row-1, j + +) 
 {
 court \u0026lt;\u0026lt;"Enter the position" \u0026lt; \u0026lt;"("\u0026lt;\u0026lt; i j \u0026lt;\u0026lt;")"\u0026lt;\u0026lt;" \u0026lt;\u0026lt;")"\u0026lt;\u0026lt;"("\u0026lt;\u0026lt; Matrix 1 \u0026lt;\u0026lt;endl; 
 cin>> array1 [i] [j];}} 
 
 
 system ("pause"); 
   int array2 [fil] [row]; 
  is  (i = 0; i \u0026lt;= fil-a i + +) 
 {
  is  (j = 0, j \u0026lt;= row-1, j + +) 
 {
 court \u0026lt;\u0026lt;"enter the position \u0026lt;\u0026lt;"("\u0026lt;\u0026lt; and \u0026lt;\u0026lt;")"\u0026lt;\u0026lt;"("\u0026lt;\u0026lt; j \u0026lt;\u0026lt;")"\u0026lt;\u0026lt;" matrix  2"<<endl; 
             cin >>matriz2[i][j]; 
         } 
     } 
     system("pause"); 
     cout << "A continuacion se sumaran las matrices ingresadas "<<endl; 
     system("pause"); 
       int   matriz3[fil][row]; 
       for    (i=0;i<=fil-1;i++) 
     { 
           for    (j=0;j<=row-1;j++) 
         { 
             matriz3[i][j]= matriz1[i][j]+matriz2[i][j]; 
             cout << "Valor posicion "\u0026lt;\u0026lt;"("\u0026lt;\u0026lt; I j \u0026lt;\u0026lt;")"\u0026lt;\u0026lt;"("\u0026lt;\u0026lt; \u0026lt;\u0026lt;"): "\u0026lt;\u0026lt;arr3 [i] [j] \u0026lt; , \u0026lt;endl;} 
 
 
} court \u0026lt;\u0026lt;"Thank you for using this program" \u0026lt;\u0026lt;endl; 
 system ("pause"); 
   return 0;} 
 
 

If you compile and run the program in Dev-C will be the summation results are printed in plain text, but restructuring the cycle for the print, it is possible to achieve an attractive graphical in printing the result matrix.

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Split a numeric array by as

Perhaps the title of the exercise is not very explicit in itself, but the idea is: You must enter
few integers to use, and then when you finish entering all values, which has to be determined been the largest number of all patients admitted to subsequently take each element of the array and divide by that number higher.

Here goes:

 
  # include \u0026lt;iostream>  
 
   using namespace std; 
 
   int size, i, j; 
   double array [20]; 
   double greater; 
 
   int main (void  ) 
 
 {court \u0026lt;\u0026lt;"Please enter how many numbers you wish to use" \u0026lt;\u0026lt;endl; 
 cin>> size; 
  for  (i = 0; i \u0026lt;size; i + +) {
 
 court \u0026lt;\u0026lt;"Please enter data" \u0026lt;\u0026lt;endl; 
 cin>> array [i]; 
 largest = array [i] ; 
   if (array [i]> highest) {
 
 higher = array [i];} 
 
 
 
  } for (j = 0, j \u0026lt;size; j + +) {
 
 array [j] = (array [j] / highest); 
 court \u0026lt;\u0026lt;"The resulting division between the number" \u0026lt;\u0026lt; j +1 \u0026lt;\u0026lt;"and the largest is" \u0026lt;\u0026lt;array [j] \u0026lt;\u0026lt;endl;} 
 
 system ("pause"); 
   return 0;} 
 
 

We used , as in most basic exercises in Dev-C + + , conditional and cycles, and although it seems that most frequently used are used for instruction , also can structure the program to work using the command while, most of all, this is at the convenience of the programmer.

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Serie Fibonacci: Print first 'n' numbers

programming in general, not just C language, use of exercises related to the Fibonacci series is a classic, and in this exercise, the idea is to print the first n numbers series, where n is a predefined value and restrictions of language should not be a very large number.

We will print the first 20 numbers in Dev-C series.

 
  # include \u0026lt;iostream>  
 
   using namespace std; 
 
  int previous1 , anterior2, current, i; 
 
   int main (void  ) 
 
 {court \u0026lt;\u0026lt;"This program will print the first 20 numbers in the series of Fibbonacci "\u0026lt;\u0026lt;endl; 
 system (" pause "); 
 previous1 = 0; 
 anterior2 = 1; 
 court \u0026lt;\u0026lt;previous1 \u0026lt;\u0026lt;endl; 
 court \u0026lt;\u0026lt;anterior2 \u0026lt;\u0026lt;endl ; 
   for (i = 1; i \u0026lt;= 20; i + +) 
 / * The 20 refers to the amount of numbers to print * / 
 
 {+ current = anterior2 previous1, previous1 = anterior2 
; 
 court \u0026lt;\u0026lt;today \u0026lt;\u0026lt;endl; 
 anterior2 = current;} 
 
 system ("pause"); 
   return 0; 
 
} 

Also in this case, it is possible to modify the program so that the user enter the value of 'n', and it would be better instead to report the numbers as int, long double it as , embracing a greater number of digits when the numbers start to become very large, and would read:

 
  previous1  long double, anterior2, current, i; 
 
   long double main (void  ) 
 

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Print odd and even numbers from 1 to 'n'

This is a simple example of the combined use of cycles ( For in this case) and conditionals.
The first idea is to print all the odd numbers from 1 to n, then the couple, noting that "n" is a predefined value, although it could be a simple modification for the user to enter the number.
we go.

 
 \u0026lt;iostream>   # include using namespace 
 
   std; 
 
   int a, b, c, d; 
 
   int main (void) {
 
 court \u0026lt;\u0026lt;"Printing of odd numbers from 1 to 999" \u0026lt;\u0026lt;endl \u0026lt;\u0026lt; ; endl; 
 system ("pause"); 
  for  (a = 1, a \u0026lt;= 1000; a + +) 
 {
 b = a% 2; 
  if  (b == 1) 
 {
 court \u0026lt;\u0026lt;a \u0026lt;\u0026lt;endl;} 
 
 
} system ("pause"); 
 court \u0026lt;\u0026lt;"Print the even numbers from 1 to 1000" \u0026lt;\u0026lt;Endl \u0026lt;\u0026lt;endl; 
 system ("pause"); 
   for (d = 1, d \u0026lt;= 1000; d + +) {
 
 c = d% 2; 
   if (c = = 0) 
 
 {court \u0026lt;\u0026lt;d \u0026lt;\u0026lt;endl;} 
 
 
} system ("pause"); 
   return 0;}